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6(2x-8)-3=6(x-2)+3
We move all terms to the left:
6(2x-8)-3-(6(x-2)+3)=0
We multiply parentheses
12x-(6(x-2)+3)-48-3=0
We calculate terms in parentheses: -(6(x-2)+3), so:We add all the numbers together, and all the variables
6(x-2)+3
We multiply parentheses
6x-12+3
We add all the numbers together, and all the variables
6x-9
Back to the equation:
-(6x-9)
12x-(6x-9)-51=0
We get rid of parentheses
12x-6x+9-51=0
We add all the numbers together, and all the variables
6x-42=0
We move all terms containing x to the left, all other terms to the right
6x=42
x=42/6
x=7
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