13(x+3)-4(x-4)=4(x-4)+4(x-4)

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Solution for 13(x+3)-4(x-4)=4(x-4)+4(x-4) equation: 



13(x+3)-4(x-4)=4(x-4)+4(x-4)

We move all terms to the left:

13(x+3)-4(x-4)-(4(x-4)+4(x-4))=0

We multiply parentheses

13x-4x-(4(x-4)+4(x-4))+39+16=0



We calculate terms in parentheses: -(4(x-4)+4(x-4)), so:

4(x-4)+4(x-4)

We multiply parentheses

4x+4x-16-16

We add all the numbers together, and all the variables

8x-32

Back to the equation:

-(8x-32)



We add all the numbers together, and all the variables

9x-(8x-32)+55=0

We get rid of parentheses

9x-8x+32+55=0

We add all the numbers together, and all the variables

x+87=0

We move all terms containing x to the left, all other terms to the right

x=-87

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