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(x+2)(6x+10)=180
We move all terms to the left:
(x+2)(6x+10)-(180)=0
We multiply parentheses ..
(+6x^2+10x+12x+20)-180=0
We get rid of parentheses
6x^2+10x+12x+20-180=0
We add all the numbers together, and all the variables
6x^2+22x-160=0
a = 6; b = 22; c = -160;
Δ = b2-4ac
Δ = 222-4·6·(-160)
Δ = 4324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4324}=\sqrt{4*1081}=\sqrt{4}*\sqrt{1081}=2\sqrt{1081}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{1081}}{2*6}=\frac{-22-2\sqrt{1081}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{1081}}{2*6}=\frac{-22+2\sqrt{1081}}{12} $
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