6(2x-4)=36(2x+3)

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Solution for 6(2x-4)=36(2x+3) equation: 



6(2x-4)=36(2x+3)

We move all terms to the left:

6(2x-4)-(36(2x+3))=0

We multiply parentheses

12x-(36(2x+3))-24=0



We calculate terms in parentheses: -(36(2x+3)), so:

36(2x+3)

We multiply parentheses

72x+108

Back to the equation:

-(72x+108)



We get rid of parentheses

12x-72x-108-24=0

We add all the numbers together, and all the variables

-60x-132=0

We move all terms containing x to the left, all other terms to the right

-60x=132

x=132/-60

x=-2+1/5

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