-2n+4(n-5)=6(3n-2)

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Solution for -2n+4(n-5)=6(3n-2) equation: 



-2n+4(n-5)=6(3n-2)

We move all terms to the left:

-2n+4(n-5)-(6(3n-2))=0

We multiply parentheses

-2n+4n-(6(3n-2))-20=0



We calculate terms in parentheses: -(6(3n-2)), so:

6(3n-2)

We multiply parentheses

18n-12

Back to the equation:

-(18n-12)



We add all the numbers together, and all the variables

2n-(18n-12)-20=0

We get rid of parentheses

2n-18n+12-20=0

We add all the numbers together, and all the variables

-16n-8=0

We move all terms containing n to the left, all other terms to the right

-16n=8

n=8/-16

n=-1/2

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