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6(2x-3)=10(2x-5)
We move all terms to the left:
6(2x-3)-(10(2x-5))=0
We multiply parentheses
12x-(10(2x-5))-18=0
We calculate terms in parentheses: -(10(2x-5)), so:We get rid of parentheses
10(2x-5)
We multiply parentheses
20x-50
Back to the equation:
-(20x-50)
12x-20x+50-18=0
We add all the numbers together, and all the variables
-8x+32=0
We move all terms containing x to the left, all other terms to the right
-8x=-32
x=-32/-8
x=+4
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