Y-1=2x(x-0)

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Solution for Y-1=2x(x-0) equation: 



-1=2Y(Y-0)

We move all terms to the left:

-1-(2Y(Y-0))=0

We add all the numbers together, and all the variables

-(2Y(+Y))-1=0



We calculate terms in parentheses: -(2Y(+Y)), so:

2Y(+Y)

We multiply parentheses

2Y^2

Back to the equation:

-(2Y^2)



a = -2; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-2)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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