3(1-x)+2x-5=7x-(4x-2)-6

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Solution for 3(1-x)+2x-5=7x-(4x-2)-6 equation: 



3(1-x)+2x-5=7x-(4x-2)-6

We move all terms to the left:

3(1-x)+2x-5-(7x-(4x-2)-6)=0

We add all the numbers together, and all the variables

3(-1x+1)+2x-(7x-(4x-2)-6)-5=0

We add all the numbers together, and all the variables

2x+3(-1x+1)-(7x-(4x-2)-6)-5=0

We multiply parentheses

2x-3x-(7x-(4x-2)-6)+3-5=0



We calculate terms in parentheses: -(7x-(4x-2)-6), so:

7x-(4x-2)-6

We get rid of parentheses

7x-4x+2-6

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

-1x-(3x-4)-2=0

We get rid of parentheses

-1x-3x+4-2=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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