6(2t+4)-5(t-3)=4

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Solution for 6(2t+4)-5(t-3)=4 equation: 



6(2t+4)-5(t-3)=4

We move all terms to the left:

6(2t+4)-5(t-3)-(4)=0

We multiply parentheses

12t-5t+24+15-4=0

We add all the numbers together, and all the variables

7t+35=0

We move all terms containing t to the left, all other terms to the right

7t=-35

t=-35/7

t=-5

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