9(t-2)=3(t-12)

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Solution for 9(t-2)=3(t-12) equation: 



9(t-2)=3(t-12)

We move all terms to the left:

9(t-2)-(3(t-12))=0

We multiply parentheses

9t-(3(t-12))-18=0



We calculate terms in parentheses: -(3(t-12)), so:

3(t-12)

We multiply parentheses

3t-36

Back to the equation:

-(3t-36)



We get rid of parentheses

9t-3t+36-18=0

We add all the numbers together, and all the variables

6t+18=0

We move all terms containing t to the left, all other terms to the right

6t=-18

t=-18/6

t=-3

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