-5x(2x+3)=0

Solution for -5x(2x+3)=0 equation:

-5x(2x+3)=0

We multiply parentheses

-10x^2-15x=0

a = -10; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-10)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-10}=\frac{0}{-20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-10}=\frac{30}{-20}
=-1+1/2
$