6(2a+1)+5=-2+3(4a-3)

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Solution for 6(2a+1)+5=-2+3(4a-3) equation: 



6(2a+1)+5=-2+3(4a-3)

We move all terms to the left:

6(2a+1)+5-(-2+3(4a-3))=0

We multiply parentheses

12a-(-2+3(4a-3))+6+5=0



We calculate terms in parentheses: -(-2+3(4a-3)), so:

-2+3(4a-3)

determiningTheFunctionDomain
3(4a-3)-2

We multiply parentheses

12a-9-2

We add all the numbers together, and all the variables

12a-11

Back to the equation:

-(12a-11)



We add all the numbers together, and all the variables

12a-(12a-11)+11=0

We get rid of parentheses

12a-12a+11+11=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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