7(-4+3-2)=6(5+2t-7)

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Solution for 7(-4+3-2)=6(5+2t-7) equation: 



7(-4+3-2)=6(5+2t-7)

We move all terms to the left:

7(-4+3-2)-(6(5+2t-7))=0

We add all the numbers together, and all the variables

-(6(2t-2))+7(-3)=0

We add all the numbers together, and all the variables

-(6(2t-2))-21=0



We calculate terms in parentheses: -(6(2t-2)), so:

6(2t-2)

We multiply parentheses

12t-12

Back to the equation:

-(12t-12)



We get rid of parentheses

-12t+12-21=0

We add all the numbers together, and all the variables

-12t-9=0

We move all terms containing t to the left, all other terms to the right

-12t=9

t=9/-12

t=-3/4

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