1/3(2n+7)=1/5(n-12)

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Solution for 1/3(2n+7)=1/5(n-12) equation: 



1/3(2n+7)=1/5(n-12)

We move all terms to the left:

1/3(2n+7)-(1/5(n-12))=0



Domain of the equation: 3(2n+7)!=0

n∈R





Domain of the equation: 5(n-12))!=0

n∈R



We calculate fractions


(5nn/(3(2n+7)*5(n-12)))+(-3n2/(3(2n+7)*5(n-12)))=0



We calculate terms in parentheses: +(5nn/(3(2n+7)*5(n-12))), so:

5nn/(3(2n+7)*5(n-12))

We multiply all the terms by the denominator


5nn

Back to the equation:

+(5nn)





We calculate terms in parentheses: +(-3n2/(3(2n+7)*5(n-12))), so:

-3n2/(3(2n+7)*5(n-12))

We multiply all the terms by the denominator


-3n2

We add all the numbers together, and all the variables

-3n^2

Back to the equation:

+(-3n^2)



We get rid of parentheses

-3n^2+5nn=0

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