6(20-x)=4(20+x)

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Solution for 6(20-x)=4(20+x) equation: 



6(20-x)=4(20+x)

We move all terms to the left:

6(20-x)-(4(20+x))=0

We add all the numbers together, and all the variables

6(-1x+20)-(4(x+20))=0

We multiply parentheses

-6x-(4(x+20))+120=0



We calculate terms in parentheses: -(4(x+20)), so:

4(x+20)

We multiply parentheses

4x+80

Back to the equation:

-(4x+80)



We get rid of parentheses

-6x-4x-80+120=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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