3/4(20-x)=1/2(20+x)

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Solution for 3/4(20-x)=1/2(20+x) equation: 



3/4(20-x)=1/2(20+x)

We move all terms to the left:

3/4(20-x)-(1/2(20+x))=0



Domain of the equation: 4(20-x)!=0

x∈R





Domain of the equation: 2(20+x))!=0

x∈R



We add all the numbers together, and all the variables

3/4(-1x+20)-(1/2(x+20))=0

We calculate fractions


(6xx/(4(-1x+20)*2(x+20)))+(-4x0/(4(-1x+20)*2(x+20)))=0



We calculate terms in parentheses: +(6xx/(4(-1x+20)*2(x+20))), so:

6xx/(4(-1x+20)*2(x+20))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-4x0/(4(-1x+20)*2(x+20))), so:

-4x0/(4(-1x+20)*2(x+20))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

6xx-4x=0

We add all the numbers together, and all the variables

-4x+6xx=0

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