3(20-x)/4=1(20+x)/2

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Solution for 3(20-x)/4=1(20+x)/2 equation: 



3(20-x)/4=1(20+x)/2

We move all terms to the left:

3(20-x)/4-(1(20+x)/2)=0

We add all the numbers together, and all the variables

3(-1x+20)/4-(1(x+20)/2)=0

We calculate fractions


(-3x)/()+(-(1(x+20)*4)/()=0



We calculate terms in parentheses: +(-(1(x+20)*4)/(), so:

-(1(x+20)*4)/(

We multiply all the terms by the denominator


-(1(x+20)*4)



We calculate terms in parentheses: -(1(x+20)*4), so:

1(x+20)*4

We multiply parentheses

4x+80

Back to the equation:

-(4x+80)



We get rid of parentheses

-4x-80

Back to the equation:

+(-4x-80)



We get rid of parentheses

(-3x)/()-4x-80=0

We multiply all the terms by the denominator


(-3x)-4x*()-80*()=0

We add all the numbers together, and all the variables

(-3x)-4x*()=0

We get rid of parentheses

-3x-4x*()=0

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