6(1-4b)+5(b-2)=15

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Solution for 6(1-4b)+5(b-2)=15 equation:



6(1-4b)+5(b-2)=15
We move all terms to the left:
6(1-4b)+5(b-2)-(15)=0
We add all the numbers together, and all the variables
6(-4b+1)+5(b-2)-15=0
We multiply parentheses
-24b+5b+6-10-15=0
We add all the numbers together, and all the variables
-19b-19=0
We move all terms containing b to the left, all other terms to the right
-19b=19
b=19/-19
b=-1

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