-3(3y-7)+3y=6(y+6)

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Solution for -3(3y-7)+3y=6(y+6) equation: 



-3(3y-7)+3y=6(y+6)

We move all terms to the left:

-3(3y-7)+3y-(6(y+6))=0

We add all the numbers together, and all the variables

3y-3(3y-7)-(6(y+6))=0

We multiply parentheses

3y-9y-(6(y+6))+21=0



We calculate terms in parentheses: -(6(y+6)), so:

6(y+6)

We multiply parentheses

6y+36

Back to the equation:

-(6y+36)



We add all the numbers together, and all the variables

-6y-(6y+36)+21=0

We get rid of parentheses

-6y-6y-36+21=0

We add all the numbers together, and all the variables

-12y-15=0

We move all terms containing y to the left, all other terms to the right

-12y=15

y=15/-12

y=-1+1/4

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