4(n+2)=11n-5

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Solution for 4(n+2)=11n-5 equation:



4(n+2)=11n-5
We move all terms to the left:
4(n+2)-(11n-5)=0
We multiply parentheses
4n-(11n-5)+8=0
We get rid of parentheses
4n-11n+5+8=0
We add all the numbers together, and all the variables
-7n+13=0
We move all terms containing n to the left, all other terms to the right
-7n=-13
n=-13/-7
n=1+6/7

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