6(1+2v)+7=-5(2v-7)

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Solution for 6(1+2v)+7=-5(2v-7) equation: 



6(1+2v)+7=-5(2v-7)

We move all terms to the left:

6(1+2v)+7-(-5(2v-7))=0

We add all the numbers together, and all the variables

6(2v+1)-(-5(2v-7))+7=0

We multiply parentheses

12v-(-5(2v-7))+6+7=0



We calculate terms in parentheses: -(-5(2v-7)), so:

-5(2v-7)

We multiply parentheses

-10v+35

Back to the equation:

-(-10v+35)



We add all the numbers together, and all the variables

12v-(-10v+35)+13=0

We get rid of parentheses

12v+10v-35+13=0

We add all the numbers together, and all the variables

22v-22=0

We move all terms containing v to the left, all other terms to the right

22v=22

v=22/22

v=1

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