-2t+1.5=(t/4)-12

Solution for -2t+1.5=(t/4)-12 equation:

-2t+1.5=(t/4)-12

We move all terms to the left:

-2t+1.5-((t/4)-12)=0

We add all the numbers together, and all the variables

-2t-((+t/4)-12)+1.5=0

We multiply all the terms by the denominator


-2t*4)-12)-((+t+(1.5)*4)-12)=0

We add all the numbers together, and all the variables

t-2t*4)-12)-((=0

Wy multiply elements

-8t^2+t=0

a = -8; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-8)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-8}=\frac{-2}{-16}
=1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-8}=\frac{0}{-16}
=0
$