F(x)=-(2/5)x+4

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Solution for F(x)=-(2/5)x+4 equation: 



(F)=-(2/5)F+4

We move all terms to the left:

(F)-(-(2/5)F+4)=0



Domain of the equation: 5)F+4)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

F-(-(+2/5)F+4)=0

We multiply all the terms by the denominator


F*5)F+4)-(-(+2=0

Wy multiply elements

5F^2+2=0

a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation

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