6(1+2m)+3m=24

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Solution for 6(1+2m)+3m=24 equation: 



6(1+2m)+3m=24

We move all terms to the left:

6(1+2m)+3m-(24)=0

We add all the numbers together, and all the variables

6(2m+1)+3m-24=0

We add all the numbers together, and all the variables

3m+6(2m+1)-24=0

We multiply parentheses

3m+12m+6-24=0

We add all the numbers together, and all the variables

15m-18=0

We move all terms containing m to the left, all other terms to the right

15m=18

m=18/15

m=1+1/5

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