(x+16)(2-4x)=0

Solution for (x+16)(2-4x)=0 equation:

(x+16)(2-4x)=0

We add all the numbers together, and all the variables

(x+16)(-4x+2)=0

We multiply parentheses ..

(-4x^2+2x-64x+32)=0

We get rid of parentheses

-4x^2+2x-64x+32=0

We add all the numbers together, and all the variables

-4x^2-62x+32=0

a = -4; b = -62; c = +32;
Δ = b2-4ac
Δ = -622-4·(-4)·32
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-66}{2*-4}=\frac{-4}{-8}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+66}{2*-4}=\frac{128}{-8}
=-16
$