-3x-2(3x+4)-4=3(2-x)+2-x

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Solution for -3x-2(3x+4)-4=3(2-x)+2-x equation: 



-3x-2(3x+4)-4=3(2-x)+2-x

We move all terms to the left:

-3x-2(3x+4)-4-(3(2-x)+2-x)=0

We add all the numbers together, and all the variables

-3x-2(3x+4)-(3(-1x+2)+2-x)-4=0

We multiply parentheses

-3x-6x-(3(-1x+2)+2-x)-8-4=0



We calculate terms in parentheses: -(3(-1x+2)+2-x), so:

3(-1x+2)+2-x

determiningTheFunctionDomain
3(-1x+2)-x+2

We add all the numbers together, and all the variables

-1x+3(-1x+2)+2

We multiply parentheses

-1x-3x+6+2

We add all the numbers together, and all the variables

-4x+8

Back to the equation:

-(-4x+8)



We add all the numbers together, and all the variables

-9x-(-4x+8)-12=0

We get rid of parentheses

-9x+4x-8-12=0

We add all the numbers together, and all the variables

-5x-20=0

We move all terms containing x to the left, all other terms to the right

-5x=20

x=20/-5

x=-4

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