5y-4(4-y)=y+12

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Solution for 5y-4(4-y)=y+12 equation: 



5y-4(4-y)=y+12

We move all terms to the left:

5y-4(4-y)-(y+12)=0

We add all the numbers together, and all the variables

5y-4(-1y+4)-(y+12)=0

We multiply parentheses

5y+4y-(y+12)-16=0

We get rid of parentheses

5y+4y-y-12-16=0

We add all the numbers together, and all the variables

8y-28=0

We move all terms containing y to the left, all other terms to the right

8y=28

y=28/8

y=3+1/2

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