180=(3z+4)+(8z-28)

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Solution for 180=(3z+4)+(8z-28) equation: 



180=(3z+4)+(8z-28)

We move all terms to the left:

180-((3z+4)+(8z-28))=0



We calculate terms in parentheses: -((3z+4)+(8z-28)), so:

(3z+4)+(8z-28)

We get rid of parentheses

3z+8z+4-28

We add all the numbers together, and all the variables

11z-24

Back to the equation:

-(11z-24)



We get rid of parentheses

-11z+24+180=0

We add all the numbers together, and all the variables

-11z+204=0

We move all terms containing z to the left, all other terms to the right

-11z=-204

z=-204/-11

z=18+6/11

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