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5y+3=5(1+y)
We move all terms to the left:
5y+3-(5(1+y))=0
We add all the numbers together, and all the variables
5y-(5(y+1))+3=0
We calculate terms in parentheses: -(5(y+1)), so:We get rid of parentheses
5(y+1)
We multiply parentheses
5y+5
Back to the equation:
-(5y+5)
5y-5y-5+3=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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