128=4(2+7x)-7x

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Solution for 128=4(2+7x)-7x equation: 



128=4(2+7x)-7x

We move all terms to the left:

128-(4(2+7x)-7x)=0

We add all the numbers together, and all the variables

-(4(7x+2)-7x)+128=0



We calculate terms in parentheses: -(4(7x+2)-7x), so:

4(7x+2)-7x

We add all the numbers together, and all the variables

-7x+4(7x+2)

We multiply parentheses

-7x+28x+8

We add all the numbers together, and all the variables

21x+8

Back to the equation:

-(21x+8)



We get rid of parentheses

-21x-8+128=0

We add all the numbers together, and all the variables

-21x+120=0

We move all terms containing x to the left, all other terms to the right

-21x=-120

x=-120/-21

x=5+5/7

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