4f+40=190-2f

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Solution for 4f+40=190-2f equation: 



4f+40=190-2f

We move all terms to the left:

4f+40-(190-2f)=0

We add all the numbers together, and all the variables

4f-(-2f+190)+40=0

We get rid of parentheses

4f+2f-190+40=0

We add all the numbers together, and all the variables

6f-150=0

We move all terms containing f to the left, all other terms to the right

6f=150

f=150/6

f=25

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