3x+6=(21+3x)/2

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Solution for 3x+6=(21+3x)/2 equation:



3x+6=(21+3x)/2
We move all terms to the left:
3x+6-((21+3x)/2)=0
We add all the numbers together, and all the variables
3x-((3x+21)/2)+6=0
We multiply all the terms by the denominator
3x*2)-((3x+21)+6*2)=0
We add all the numbers together, and all the variables
3x*2)-((3x+21)=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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