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5x^2-68x=192
We move all terms to the left:
5x^2-68x-(192)=0
a = 5; b = -68; c = -192;
Δ = b2-4ac
Δ = -682-4·5·(-192)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-92}{2*5}=\frac{-24}{10} =-2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+92}{2*5}=\frac{160}{10} =16 $
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