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2x^2-9x-221=0
a = 2; b = -9; c = -221;
Δ = b2-4ac
Δ = -92-4·2·(-221)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-43}{2*2}=\frac{-34}{4} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+43}{2*2}=\frac{52}{4} =13 $
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