If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-10x-11=9
We move all terms to the left:
5x^2-10x-11-(9)=0
We add all the numbers together, and all the variables
5x^2-10x-20=0
a = 5; b = -10; c = -20;
Δ = b2-4ac
Δ = -102-4·5·(-20)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{5}}{2*5}=\frac{10-10\sqrt{5}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{5}}{2*5}=\frac{10+10\sqrt{5}}{10} $
| 17/7=10/u | | 5x-10x-11=9 | | A+1-26=a | | 10/u=17/7 | | 3x+4(-4x-11)=18 | | 90=6y-1 | | 3(x-5)=6(1+2x) | | 6a–17=1 | | 1/2x=8+3/x | | (8+2x)(26+2x)=1144 | | 3(x-14)=17x | | 3/3=2/x | | (x-9)^2+4=85 | | F(x)=X^25^-x | | -2-5b+1+8b=8(-3-6b)-5(8+6b) | | 7-5(2x+3)=9 | | -8(2r-8)-8r=(3+2r) | | 7-5(2x+3=9 | | 32r+26=-39 | | k2+4k-5=0 | | H(t)=t^2+19t+14 | | 2y-7=5y-1 | | x-3(-4.5)=3 | | 2(x+5)+20=100 | | 2a-15=3a-6 | | -8(2r8)-8r=(3+2r) | | 3a2+3a+1=0 | | 3^2+3x-5=13 | | 1x+16=4x-11 | | 2x+2=x+11, | | x−67+8=−1 | | -42.5=3y-31.7 |