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(8+2x)(26+2x)=1144
We move all terms to the left:
(8+2x)(26+2x)-(1144)=0
We add all the numbers together, and all the variables
(2x+8)(2x+26)-1144=0
We multiply parentheses ..
(+4x^2+52x+16x+208)-1144=0
We get rid of parentheses
4x^2+52x+16x+208-1144=0
We add all the numbers together, and all the variables
4x^2+68x-936=0
a = 4; b = 68; c = -936;
Δ = b2-4ac
Δ = 682-4·4·(-936)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-140}{2*4}=\frac{-208}{8} =-26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+140}{2*4}=\frac{72}{8} =9 $
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