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5x/2x=4/5
We move all terms to the left:
5x/2x-(4/5)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5x/2x-(+4/5)=0
We get rid of parentheses
5x/2x-4/5=0
We calculate fractions
25x/10x+(-8x)/10x=0
We multiply all the terms by the denominator
25x+(-8x)=0
We get rid of parentheses
25x-8x=0
We add all the numbers together, and all the variables
17x=0
x=0/17
x=0
Równanie nie ma rozwiązania
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