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2(3x+4)=5(3+2x)5-4x
We move all terms to the left:
2(3x+4)-(5(3+2x)5-4x)=0
We add all the numbers together, and all the variables
2(3x+4)-(5(2x+3)5-4x)=0
We multiply parentheses
6x-(5(2x+3)5-4x)+8=0
We calculate terms in parentheses: -(5(2x+3)5-4x), so:We get rid of parentheses
5(2x+3)5-4x
We add all the numbers together, and all the variables
-4x+5(2x+3)5
We multiply parentheses
-4x+50x+75
We add all the numbers together, and all the variables
46x+75
Back to the equation:
-(46x+75)
6x-46x-75+8=0
We add all the numbers together, and all the variables
-40x-67=0
We move all terms containing x to the left, all other terms to the right
-40x=67
x=67/-40
x=-1+27/40
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