(8-2x)(12-2x)=59.52

Solution for (8-2x)(12-2x)=59.52 equation:

(8-2x)(12-2x)=59.52

We move all terms to the left:

(8-2x)(12-2x)-(59.52)=0

We add all the numbers together, and all the variables

(-2x+8)(-2x+12)-(59.52)=0

We add all the numbers together, and all the variables

(-2x+8)(-2x+12)-59.52=0

We multiply parentheses ..

(+4x^2-24x-16x+96)-59.52=0

We get rid of parentheses

4x^2-24x-16x+96-59.52=0

We add all the numbers together, and all the variables

4x^2-40x+36.48=0

a = 4; b = -40; c = +36.48;
Δ = b2-4ac
Δ = -402-4·4·36.48
Δ = 1016.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{1016.32}}{2*4}=\frac{40-\sqrt{1016.32}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{1016.32}}{2*4}=\frac{40+\sqrt{1016.32}}{8}
$