12-3(a-15)=10+5(5-a)

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Solution for 12-3(a-15)=10+5(5-a) equation: 



12-3(a-15)=10+5(5-a)

We move all terms to the left:

12-3(a-15)-(10+5(5-a))=0

We add all the numbers together, and all the variables

-3(a-15)-(10+5(-1a+5))+12=0

We multiply parentheses

-3a-(10+5(-1a+5))+45+12=0



We calculate terms in parentheses: -(10+5(-1a+5)), so:

10+5(-1a+5)

determiningTheFunctionDomain
5(-1a+5)+10

We multiply parentheses

-5a+25+10

We add all the numbers together, and all the variables

-5a+35

Back to the equation:

-(-5a+35)



We add all the numbers together, and all the variables

-3a-(-5a+35)+57=0

We get rid of parentheses

-3a+5a-35+57=0

We add all the numbers together, and all the variables

2a+22=0

We move all terms containing a to the left, all other terms to the right

2a=-22

a=-22/2

a=-11

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