5x-4/x+1=4

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Solution for 5x-4/x+1=4 equation:



5x-4/x+1=4
We move all terms to the left:
5x-4/x+1-(4)=0
Domain of the equation: x!=0
x∈R
We add all the numbers together, and all the variables
5x-4/x-3=0
We multiply all the terms by the denominator
5x*x-3*x-4=0
We add all the numbers together, and all the variables
-3x+5x*x-4=0
Wy multiply elements
5x^2-3x-4=0
a = 5; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·5·(-4)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*5}=\frac{3-\sqrt{89}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*5}=\frac{3+\sqrt{89}}{10} $

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