9a-3(2a-5)=7(a-1)-a+10

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Solution for 9a-3(2a-5)=7(a-1)-a+10 equation: 



9a-3(2a-5)=7(a-1)-a+10

We move all terms to the left:

9a-3(2a-5)-(7(a-1)-a+10)=0

We multiply parentheses

9a-6a-(7(a-1)-a+10)+15=0



We calculate terms in parentheses: -(7(a-1)-a+10), so:

7(a-1)-a+10

We add all the numbers together, and all the variables

-1a+7(a-1)+10

We multiply parentheses

-1a+7a-7+10

We add all the numbers together, and all the variables

6a+3

Back to the equation:

-(6a+3)



We add all the numbers together, and all the variables

3a-(6a+3)+15=0

We get rid of parentheses

3a-6a-3+15=0

We add all the numbers together, and all the variables

-3a+12=0

We move all terms containing a to the left, all other terms to the right

-3a=-12

a=-12/-3

a=+4

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