44w-(w+29)=3(w+5)-(2w+4)

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Solution for 44w-(w+29)=3(w+5)-(2w+4) equation: 



44w-(w+29)=3(w+5)-(2w+4)

We move all terms to the left:

44w-(w+29)-(3(w+5)-(2w+4))=0

We get rid of parentheses

44w-w-(3(w+5)-(2w+4))-29=0



We calculate terms in parentheses: -(3(w+5)-(2w+4)), so:

3(w+5)-(2w+4)

We multiply parentheses

3w-(2w+4)+15

We get rid of parentheses

3w-2w-4+15

We add all the numbers together, and all the variables

w+11

Back to the equation:

-(w+11)



We add all the numbers together, and all the variables

43w-(w+11)-29=0

We get rid of parentheses

43w-w-11-29=0

We add all the numbers together, and all the variables

42w-40=0

We move all terms containing w to the left, all other terms to the right

42w=40

w=40/42

w=20/21

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