5x-2(3x+1)=3(x-5)-3

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Solution for 5x-2(3x+1)=3(x-5)-3 equation: 



5x-2(3x+1)=3(x-5)-3

We move all terms to the left:

5x-2(3x+1)-(3(x-5)-3)=0

We multiply parentheses

5x-6x-(3(x-5)-3)-2=0



We calculate terms in parentheses: -(3(x-5)-3), so:

3(x-5)-3

We multiply parentheses

3x-15-3

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

-1x-(3x-18)-2=0

We get rid of parentheses

-1x-3x+18-2=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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