F(x)=x2+3x+1

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Solution for F(x)=x2+3x+1 equation: 



(F)=F2+3F+1

We move all terms to the left:

(F)-(F2+3F+1)=0

We add all the numbers together, and all the variables

-(+F^2+3F+1)+F=0

We get rid of parentheses

-F^2-3F+F-1=0

We add all the numbers together, and all the variables

-1F^2-2F-1=0

a = -1; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{2}{-2}=-1$

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