(5/6)x+17=(1/6)x-5

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Solution for (5/6)x+17=(1/6)x-5 equation:



(5/6)x+17=(1/6)x-5
We move all terms to the left:
(5/6)x+17-((1/6)x-5)=0
Domain of the equation: 6)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 6)x-5)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+5/6)x-((+1/6)x-5)+17=0
We multiply parentheses
5x^2-((+1/6)x-5)+17=0
We multiply all the terms by the denominator
5x^2*6)x-5)-((+17*6)x-5)+1=0
We add all the numbers together, and all the variables
5x^2*6)x-5)-(102x-5)+1=0
Wy multiply elements
30x^3=0
We do not support expression: x^3

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