5x-1(x+3)=7+2(x+2)

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Solution for 5x-1(x+3)=7+2(x+2) equation: 



5x-1(x+3)=7+2(x+2)

We move all terms to the left:

5x-1(x+3)-(7+2(x+2))=0



We calculate terms in parentheses: -(7+2(x+2)), so:

7+2(x+2)

determiningTheFunctionDomain
2(x+2)+7

We multiply parentheses

2x+4+7

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

5x-1(x+3)-2x-11=0

We add all the numbers together, and all the variables

3x-1(x+3)-11=0

We move all terms containing x to the left, all other terms to the right

3x-1(x+3)=11

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