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x(6+x)-2(x+1)-5x=4-2.0
We move all terms to the left:
x(6+x)-2(x+1)-5x-(4-2.0)=0
We add all the numbers together, and all the variables
x(x+6)-2(x+1)-5x-2=0
We add all the numbers together, and all the variables
-5x+x(x+6)-2(x+1)-2=0
We multiply parentheses
x^2-5x+6x-2x-2-2=0
We add all the numbers together, and all the variables
x^2-1x-4=0
a = 1; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*1}=\frac{1-\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*1}=\frac{1+\sqrt{17}}{2} $
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