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2(a+5)-3=5-3(a+1)
We move all terms to the left:
2(a+5)-3-(5-3(a+1))=0
We multiply parentheses
2a-(5-3(a+1))+10-3=0
We calculate terms in parentheses: -(5-3(a+1)), so:We add all the numbers together, and all the variables
5-3(a+1)
determiningTheFunctionDomain -3(a+1)+5
We multiply parentheses
-3a-3+5
We add all the numbers together, and all the variables
-3a+2
Back to the equation:
-(-3a+2)
2a-(-3a+2)+7=0
We get rid of parentheses
2a+3a-2+7=0
We add all the numbers together, and all the variables
5a+5=0
We move all terms containing a to the left, all other terms to the right
5a=-5
a=-5/5
a=-1
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