5x+2(x-7)=3(x+1)-2

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Solution for 5x+2(x-7)=3(x+1)-2 equation: 



5x+2(x-7)=3(x+1)-2

We move all terms to the left:

5x+2(x-7)-(3(x+1)-2)=0

We multiply parentheses

5x+2x-(3(x+1)-2)-14=0



We calculate terms in parentheses: -(3(x+1)-2), so:

3(x+1)-2

We multiply parentheses

3x+3-2

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

7x-(3x+1)-14=0

We get rid of parentheses

7x-3x-1-14=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

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